Differential question ?
The answer i have is -25x / (2 root 7) + 4/x but im not sure right.
Can you show me how you came to your answer. Many Thanks
We differentiate the two parts 5 / (sq.root 7x^5) and 4 ln (2x) separately.
Firstly, the differential of 4 ln (2x) is of course 4/x, you know how to do this don't you?
Secondly, we differentiate f(x)= 5 / (sq.root 7x^5). We calculate the derivative of g(x)= (root (7x^5)) first. Note that g(x) = root 7 x^(5/2), and using power rule we know that g'(x) = root 7 * 5/2 x ^(3/2). Now, use the quotient rule, to get
f'(x) = (-5 root 7 * 5/2 x ^(3/2)) / (7x^5) = -25 / (2 root 7 x^(7/2)).
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