Physics help needed desperately?
(a) What is the magnitude and direction of the force that the paraglider exerts on the earth?
(b) If the lift force should suddenly decrease to 700 N, what would be the vertical acceleration of the glider?
If the lift force decreased to 700 N, the vertical accerlation would be 1500-700 - (mass of glider in kilograms) times (9.8 meters/second squared). = 800 - mass*9.8
Or weight + lift force = 0
Or weight + 1500 N = 0
Or weight = -1500 N
Weight of the paraglider is the force by the Earth on the paraglider.
So, Earth exerts force -1500 N on the paraglider.
By Newton's third law, the paraglider exerts force +1500 N on the Earth.
This is positive means that the force is upward.
Ans: 1500 N in upward direction.
b)Weight = -1500 N
Lift force = 700 N
Net force F = -1500 + 700 = -800 N
Magnitude of acceleration due to gravity = 9.8 m/s^2
Mass M = magnitude of weight/9.8 = 1500/9.8 kg = 153.06 kg
Acceleration a = F/m = -800/153.06 = -5.23 m/s^2
It is negative, which means that acceleration is 5.23 m/s^2 downward.
Ans: 5.23 m/s^2 in downward direction
(a) As the paraglider horizontally at a constant speed so the magnitude that the paraglider exerts on earth is 1500 N in +y direction. This is because both the upward force and its weight cancel each other. and the earth exerts force on the glider equal to its weight in -y direction and glider exerts force on the earth equal to its weight in +y direction which both are 1500 N.
(b) Weight of paraglider = 1500 N
mass = 1500/9.81 = 152.905 Kg
Now if the force of uplift is decreased to 700 N, therefore the paraglider has a net force acting on him exerted by earth equal to 1500 - 700 = 800 N in -y direction
Now acceleration = Net Force/mass = 800/152.905 = 5.232 m/sec^2 in -y direction
Hope this is helpful, keep smiling, bye
b)-8*g/15
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